Base | Representation |
---|---|
bin | 110010101101011110… |
… | …000101011011100001 |
3 | 12012112201012011211201 |
4 | 302231132011123201 |
5 | 1343003141434411 |
6 | 41003003241201 |
7 | 3635214650101 |
oct | 625536053341 |
9 | 165481164751 |
10 | 54449952481 |
11 | 21101640231 |
12 | a677219201 |
13 | 51999725c2 |
14 | 28c772d201 |
15 | 163a3993c1 |
hex | cad7856e1 |
54449952481 has 2 divisors, whose sum is σ = 54449952482. Its totient is φ = 54449952480.
The previous prime is 54449952437. The next prime is 54449952493. The reversal of 54449952481 is 18425994445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30882790225 + 23567162256 = 175735^2 + 153516^2 .
It is a cyclic number.
It is not a de Polignac number, because 54449952481 - 211 = 54449950433 is a prime.
It is a super-2 number, since 2×544499524812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54449958481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27224976240 + 27224976241.
It is an arithmetic number, because the mean of its divisors is an integer number (27224976241).
Almost surely, 254449952481 is an apocalyptic number.
It is an amenable number.
54449952481 is a deficient number, since it is larger than the sum of its proper divisors (1).
54449952481 is an equidigital number, since it uses as much as digits as its factorization.
54449952481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8294400, while the sum is 55.
The spelling of 54449952481 in words is "fifty-four billion, four hundred forty-nine million, nine hundred fifty-two thousand, four hundred eighty-one".
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