Base | Representation |
---|---|
bin | 11000110010001011000111… |
… | …01110011111110001111001 |
3 | 21010222012100110122111200122 |
4 | 30121011203232133301321 |
5 | 24120414022331331441 |
6 | 311525105021143025 |
7 | 14323350344136131 |
oct | 1431054356376171 |
9 | 233865313574618 |
10 | 54500513152121 |
11 | 164025a0937a13 |
12 | 61426936baa75 |
13 | 24544b7a77a8a |
14 | d65ba5d87ac1 |
15 | 647a3b81334b |
hex | 319163b9fc79 |
54500513152121 has 2 divisors, whose sum is σ = 54500513152122. Its totient is φ = 54500513152120.
The previous prime is 54500513151983. The next prime is 54500513152139. The reversal of 54500513152121 is 12125131500545.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49741832678521 + 4758680473600 = 7052789^2 + 2181440^2 .
It is a cyclic number.
It is not a de Polignac number, because 54500513152121 - 226 = 54500446043257 is a prime.
It is not a weakly prime, because it can be changed into another prime (54500513152181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27250256576060 + 27250256576061.
It is an arithmetic number, because the mean of its divisors is an integer number (27250256576061).
Almost surely, 254500513152121 is an apocalyptic number.
It is an amenable number.
54500513152121 is a deficient number, since it is larger than the sum of its proper divisors (1).
54500513152121 is an equidigital number, since it uses as much as digits as its factorization.
54500513152121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 35.
Adding to 54500513152121 its reverse (12125131500545), we get a palindrome (66625644652666).
The spelling of 54500513152121 in words is "fifty-four trillion, five hundred billion, five hundred thirteen million, one hundred fifty-two thousand, one hundred twenty-one".
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