Base | Representation |
---|---|
bin | 100111101001111010101… |
… | …0011010100001001001001 |
3 | 201022000202012200012121101 |
4 | 1033103311103110021021 |
5 | 1203243333301344424 |
6 | 15331431302341401 |
7 | 1101521254510645 |
oct | 117236523241111 |
9 | 21260665605541 |
10 | 5450134012489 |
11 | 1811430624531 |
12 | 740332a2a861 |
13 | 306c3a16424a |
14 | 14bb05da1c25 |
15 | 96b85632344 |
hex | 4f4f54d4249 |
5450134012489 has 2 divisors, whose sum is σ = 5450134012490. Its totient is φ = 5450134012488.
The previous prime is 5450134012457. The next prime is 5450134012571. The reversal of 5450134012489 is 9842104310545.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3936414721600 + 1513719290889 = 1984040^2 + 1230333^2 .
It is a cyclic number.
It is not a de Polignac number, because 5450134012489 - 25 = 5450134012457 is a prime.
It is not a weakly prime, because it can be changed into another prime (5450134312489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2725067006244 + 2725067006245.
It is an arithmetic number, because the mean of its divisors is an integer number (2725067006245).
Almost surely, 25450134012489 is an apocalyptic number.
It is an amenable number.
5450134012489 is a deficient number, since it is larger than the sum of its proper divisors (1).
5450134012489 is an equidigital number, since it uses as much as digits as its factorization.
5450134012489 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 46.
The spelling of 5450134012489 in words is "five trillion, four hundred fifty billion, one hundred thirty-four million, twelve thousand, four hundred eighty-nine".
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