Base | Representation |
---|---|
bin | 100111101010100000011… |
… | …0000110111010111000001 |
3 | 201022011000102221120201202 |
4 | 1033111000300313113001 |
5 | 1203303431403100423 |
6 | 15332201050110545 |
7 | 1101564526610513 |
oct | 117250060672701 |
9 | 21264012846652 |
10 | 5451400050113 |
11 | 1811a20235316 |
12 | 740626a1b455 |
13 | 3070ac53a834 |
14 | 14bbc61a1bb3 |
15 | 96c0b864728 |
hex | 4f540c375c1 |
5451400050113 has 2 divisors, whose sum is σ = 5451400050114. Its totient is φ = 5451400050112.
The previous prime is 5451400050097. The next prime is 5451400050133. The reversal of 5451400050113 is 3110500041545.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3389398825024 + 2062001225089 = 1841032^2 + 1435967^2 .
It is a cyclic number.
It is not a de Polignac number, because 5451400050113 - 24 = 5451400050097 is a prime.
It is a super-2 number, since 2×54514000501132 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5451400050133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2725700025056 + 2725700025057.
It is an arithmetic number, because the mean of its divisors is an integer number (2725700025057).
Almost surely, 25451400050113 is an apocalyptic number.
It is an amenable number.
5451400050113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5451400050113 is an equidigital number, since it uses as much as digits as its factorization.
5451400050113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 29.
Adding to 5451400050113 its reverse (3110500041545), we get a palindrome (8561900091658).
The spelling of 5451400050113 in words is "five trillion, four hundred fifty-one billion, four hundred million, fifty thousand, one hundred thirteen".
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