Base | Representation |
---|---|
bin | 110010110011000001… |
… | …011111111011010011 |
3 | 12012210012111200120111 |
4 | 302303001133323103 |
5 | 1343201014402011 |
6 | 41020132222151 |
7 | 3640425613531 |
oct | 626301377323 |
9 | 165705450514 |
10 | 54543122131 |
11 | 2114a196a43 |
12 | a6a246a957 |
13 | 51b3064184 |
14 | 28d5c63151 |
15 | 1643650121 |
hex | cb305fed3 |
54543122131 has 2 divisors, whose sum is σ = 54543122132. Its totient is φ = 54543122130.
The previous prime is 54543122119. The next prime is 54543122171. The reversal of 54543122131 is 13122134545.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54543122131 - 223 = 54534733523 is a prime.
It is a super-2 number, since 2×545431221312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54543122093 and 54543122102.
It is not a weakly prime, because it can be changed into another prime (54543122171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27271561065 + 27271561066.
It is an arithmetic number, because the mean of its divisors is an integer number (27271561066).
Almost surely, 254543122131 is an apocalyptic number.
54543122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
54543122131 is an equidigital number, since it uses as much as digits as its factorization.
54543122131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 31.
Adding to 54543122131 its reverse (13122134545), we get a palindrome (67665256676).
The spelling of 54543122131 in words is "fifty-four billion, five hundred forty-three million, one hundred twenty-two thousand, one hundred thirty-one".
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