Search a number
-
+
545504434403 = 2112585329073
BaseRepresentation
bin1111111000000101001…
…10010001100011100011
31221011001010211111012212
413330002212101203203
532414143113400103
61054333513112335
754261052121015
oct7740246214343
91834033744185
10545504434403
111a0390039585
12898803b86ab
133c5967074c6
141c58c8801b5
15e2ca9b37d8
hex7f029918e3

545504434403 has 4 divisors (see below), whose sum is σ = 548089763688. Its totient is φ = 542919105120.

The previous prime is 545504434351. The next prime is 545504434459. The reversal of 545504434403 is 304434405545.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 545504434403 - 238 = 270626527459 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (545504437403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1292664326 + ... + 1292664747.

It is an arithmetic number, because the mean of its divisors is an integer number (137022440922).

Almost surely, 2545504434403 is an apocalyptic number.

545504434403 is a deficient number, since it is larger than the sum of its proper divisors (2585329285).

545504434403 is a wasteful number, since it uses less digits than its factorization.

545504434403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2585329284.

The product of its (nonzero) digits is 1152000, while the sum is 41.

Adding to 545504434403 its reverse (304434405545), we get a palindrome (849938839948).

The spelling of 545504434403 in words is "five hundred forty-five billion, five hundred four million, four hundred thirty-four thousand, four hundred three".

Divisors: 1 211 2585329073 545504434403