Base | Representation |
---|---|
bin | 11000110011101101010001… |
… | …11100100001010110000001 |
3 | 21011011020101021201012212211 |
4 | 30121312220330201112001 |
5 | 24122244440300022001 |
6 | 312005222304422121 |
7 | 14330224333403422 |
oct | 1431665074412601 |
9 | 234136337635784 |
10 | 54553214064001 |
11 | 1642298515a044 |
12 | 6150941017941 |
13 | 24594662602c3 |
14 | d685652a7649 |
15 | 6490c336d351 |
hex | 319da8f21581 |
54553214064001 has 4 divisors (see below), whose sum is σ = 54554871695104. Its totient is φ = 54551556432900.
The previous prime is 54553214063969. The next prime is 54553214064007. The reversal of 54553214064001 is 10046041235545.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 54553214064001 - 25 = 54553214063969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54553214064007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 828766185 + ... + 828832006.
It is an arithmetic number, because the mean of its divisors is an integer number (13638717923776).
Almost surely, 254553214064001 is an apocalyptic number.
It is an amenable number.
54553214064001 is a deficient number, since it is larger than the sum of its proper divisors (1657631103).
54553214064001 is a wasteful number, since it uses less digits than its factorization.
54553214064001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1657631102.
The product of its (nonzero) digits is 288000, while the sum is 40.
Adding to 54553214064001 its reverse (10046041235545), we get a palindrome (64599255299546).
The spelling of 54553214064001 in words is "fifty-four trillion, five hundred fifty-three billion, two hundred fourteen million, sixty-four thousand, one".
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