Base | Representation |
---|---|
bin | 11000110110010010111001… |
… | …10111111010110101111001 |
3 | 21011110201220010200120212202 |
4 | 30123021130313322311321 |
5 | 24130224041304240041 |
6 | 312114125434515545 |
7 | 14336522654303345 |
oct | 1433113467726571 |
9 | 234421803616782 |
10 | 54642132102521 |
11 | 16457664066497 |
12 | 6166017595bb5 |
13 | 2464966b79292 |
14 | d6c99c600625 |
15 | 64b579728a9b |
hex | 31b25cdfad79 |
54642132102521 has 2 divisors, whose sum is σ = 54642132102522. Its totient is φ = 54642132102520.
The previous prime is 54642132102463. The next prime is 54642132102563. The reversal of 54642132102521 is 12520123124645.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52519530785296 + 2122601317225 = 7247036^2 + 1456915^2 .
It is a cyclic number.
It is not a de Polignac number, because 54642132102521 - 234 = 54624952233337 is a prime.
It is not a weakly prime, because it can be changed into another prime (54642132102221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27321066051260 + 27321066051261.
It is an arithmetic number, because the mean of its divisors is an integer number (27321066051261).
Almost surely, 254642132102521 is an apocalyptic number.
It is an amenable number.
54642132102521 is a deficient number, since it is larger than the sum of its proper divisors (1).
54642132102521 is an equidigital number, since it uses as much as digits as its factorization.
54642132102521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 38.
The spelling of 54642132102521 in words is "fifty-four trillion, six hundred forty-two billion, one hundred thirty-two million, one hundred two thousand, five hundred twenty-one".
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