Base | Representation |
---|---|
bin | 100111110101110100001… |
… | …1011101000001100101001 |
3 | 201101110201002210202221010 |
4 | 1033223220123220030221 |
5 | 1204203202100014003 |
6 | 15351255110534133 |
7 | 1103414436061452 |
oct | 117535033501451 |
9 | 21343632722833 |
10 | 5475687891753 |
11 | 1821254078212 |
12 | 745284967349 |
13 | 309480368871 |
14 | 14d04bb28129 |
15 | 9767dc62003 |
hex | 4fae86e8329 |
5475687891753 has 4 divisors (see below), whose sum is σ = 7300917189008. Its totient is φ = 3650458594500.
The previous prime is 5475687891727. The next prime is 5475687891763. The reversal of 5475687891753 is 3571987865745.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 5475687891753 - 25 = 5475687891721 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5475687891763) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912614648623 + ... + 912614648628.
It is an arithmetic number, because the mean of its divisors is an integer number (1825229297252).
Almost surely, 25475687891753 is an apocalyptic number.
It is an amenable number.
5475687891753 is a deficient number, since it is larger than the sum of its proper divisors (1825229297255).
5475687891753 is a wasteful number, since it uses less digits than its factorization.
5475687891753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1825229297254.
The product of its digits is 1778112000, while the sum is 75.
The spelling of 5475687891753 in words is "five trillion, four hundred seventy-five billion, six hundred eighty-seven million, eight hundred ninety-one thousand, seven hundred fifty-three".
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