Base | Representation |
---|---|
bin | 11000111100010101001000… |
… | …01110110111010101110001 |
3 | 21012012120010002212212101202 |
4 | 30132022210032313111301 |
5 | 24142123222324330113 |
6 | 312353301245340545 |
7 | 14360513303122463 |
oct | 1436124416672561 |
9 | 235176102785352 |
10 | 54849487730033 |
11 | 1652759a99a497 |
12 | 619a246567755 |
13 | 247b391077b69 |
14 | d78a2d572133 |
15 | 651b63813258 |
hex | 31e2a43b7571 |
54849487730033 has 2 divisors, whose sum is σ = 54849487730034. Its totient is φ = 54849487730032.
The previous prime is 54849487729931. The next prime is 54849487730039. The reversal of 54849487730033 is 33003778494845.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34651447356304 + 20198040373729 = 5886548^2 + 4494223^2 .
It is a cyclic number.
It is not a de Polignac number, because 54849487730033 - 218 = 54849487467889 is a prime.
It is not a weakly prime, because it can be changed into another prime (54849487730039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27424743865016 + 27424743865017.
It is an arithmetic number, because the mean of its divisors is an integer number (27424743865017).
Almost surely, 254849487730033 is an apocalyptic number.
It is an amenable number.
54849487730033 is a deficient number, since it is larger than the sum of its proper divisors (1).
54849487730033 is an equidigital number, since it uses as much as digits as its factorization.
54849487730033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243855360, while the sum is 65.
The spelling of 54849487730033 in words is "fifty-four trillion, eight hundred forty-nine billion, four hundred eighty-seven million, seven hundred thirty thousand, thirty-three".
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