Base | Representation |
---|---|
bin | 110011001000011100… |
… | …000100101010011011 |
3 | 12020201020120101201021 |
4 | 303020130010222123 |
5 | 1344420004104013 |
6 | 41115525103311 |
7 | 3652350532636 |
oct | 631034045233 |
9 | 166636511637 |
10 | 54902409883 |
11 | 21313a85172 |
12 | a782857b37 |
13 | 523c61c989 |
14 | 292b86ac1d |
15 | 1664e70a8d |
hex | cc8704a9b |
54902409883 has 2 divisors, whose sum is σ = 54902409884. Its totient is φ = 54902409882.
The previous prime is 54902409871. The next prime is 54902409967. The reversal of 54902409883 is 38890420945.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54902409883 is a prime.
It is a super-2 number, since 2×549024098832 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 54902409883.
It is not a weakly prime, because it can be changed into another prime (54902407883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27451204941 + 27451204942.
It is an arithmetic number, because the mean of its divisors is an integer number (27451204942).
Almost surely, 254902409883 is an apocalyptic number.
54902409883 is a deficient number, since it is larger than the sum of its proper divisors (1).
54902409883 is an equidigital number, since it uses as much as digits as its factorization.
54902409883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2488320, while the sum is 52.
The spelling of 54902409883 in words is "fifty-four billion, nine hundred two million, four hundred nine thousand, eight hundred eighty-three".
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