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54908889307 = 151136339437
BaseRepresentation
bin110011001000110100…
…110010100011011011
312020201200202120210221
4303020310302203123
51344423133424212
641120320020511
73652456600246
oct631064624333
9166650676727
1054908889307
1121317700268
12a784a61737
135240a7ac5c
14292c67625d
151665800807
hexcc8d328db

54908889307 has 4 divisors (see below), whose sum is σ = 54945230256. Its totient is φ = 54872548360.

The previous prime is 54908889257. The next prime is 54908889331. The reversal of 54908889307 is 70398880945.

54908889307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54908889307 is a prime.

It is a super-2 number, since 2×549088893072 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54908889367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18168208 + ... + 18171229.

It is an arithmetic number, because the mean of its divisors is an integer number (13736307564).

Almost surely, 254908889307 is an apocalyptic number.

54908889307 is a deficient number, since it is larger than the sum of its proper divisors (36340949).

54908889307 is a wasteful number, since it uses less digits than its factorization.

54908889307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36340948.

The product of its (nonzero) digits is 17418240, while the sum is 61.

The spelling of 54908889307 in words is "fifty-four billion, nine hundred eight million, eight hundred eighty-nine thousand, three hundred seven".

Divisors: 1 1511 36339437 54908889307