Base | Representation |
---|---|
bin | 110011001010010110… |
… | …011101110001101001 |
3 | 12020210110221110021111 |
4 | 303022112131301221 |
5 | 1400001212304223 |
6 | 41123032510321 |
7 | 3653220332356 |
oct | 631226356151 |
9 | 166713843244 |
10 | 54934494313 |
11 | 213300a9726 |
12 | a79154b3a1 |
13 | 524617464a |
14 | 2931c1d62d |
15 | 1667bac30d |
hex | cca59dc69 |
54934494313 has 2 divisors, whose sum is σ = 54934494314. Its totient is φ = 54934494312.
The previous prime is 54934494289. The next prime is 54934494359. The reversal of 54934494313 is 31349443945.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37895630224 + 17038864089 = 194668^2 + 130533^2 .
It is a cyclic number.
It is not a de Polignac number, because 54934494313 - 217 = 54934363241 is a prime.
It is not a weakly prime, because it can be changed into another prime (54934494913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27467247156 + 27467247157.
It is an arithmetic number, because the mean of its divisors is an integer number (27467247157).
Almost surely, 254934494313 is an apocalyptic number.
It is an amenable number.
54934494313 is a deficient number, since it is larger than the sum of its proper divisors (1).
54934494313 is an equidigital number, since it uses as much as digits as its factorization.
54934494313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 49.
The spelling of 54934494313 in words is "fifty-four billion, nine hundred thirty-four million, four hundred ninety-four thousand, three hundred thirteen".
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