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549999999481 is a prime number
BaseRepresentation
bin10000000000011101000…
…11011111100111111001
31221120122110000212011011
420000032203133213321
533002344444440411
61100355544433521
754510340600522
oct10001643374771
91846573025134
10549999999481
111a2287730119
128a715a788a1
133cb31bba49a
141c897953849
15e4904c7c21
hex800e8df9f9

549999999481 has 2 divisors, whose sum is σ = 549999999482. Its totient is φ = 549999999480.

The previous prime is 549999999433. The next prime is 549999999517. The reversal of 549999999481 is 184999999945.

549999999481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 400289043856 + 149710955625 = 632684^2 + 386925^2 .

It is a cyclic number.

It is not a de Polignac number, because 549999999481 - 223 = 549991610873 is a prime.

It is a super-3 number, since 3×5499999994813 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (549999999421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 274999999740 + 274999999741.

It is an arithmetic number, because the mean of its divisors is an integer number (274999999741).

Almost surely, 2549999999481 is an apocalyptic number.

It is an amenable number.

549999999481 is a deficient number, since it is larger than the sum of its proper divisors (1).

549999999481 is an equidigital number, since it uses as much as digits as its factorization.

549999999481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3061100160, while the sum is 85.

The spelling of 549999999481 in words is "five hundred forty-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, four hundred eighty-one".