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55001167503361 = 73867744597283
BaseRepresentation
bin11001000000101111101010…
…00011010010000000000001
321012202001121221010201002021
430200113311003102000001
524202114342340101421
6312551104301321441
714404463126664202
oct1440276503220001
9235661557121067
1055001167503361
11165859561a6162
126203717866281
13248c784641221
14d820dc0615a9
15655a8eaed341
hex3205f50d2001

55001167503361 has 4 divisors (see below), whose sum is σ = 55001912174512. Its totient is φ = 55000422832212.

The previous prime is 55001167503329. The next prime is 55001167503367. The reversal of 55001167503361 is 16330576110055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55001167503361 - 25 = 55001167503329 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55001167503367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 372224775 + ... + 372372508.

It is an arithmetic number, because the mean of its divisors is an integer number (13750478043628).

Almost surely, 255001167503361 is an apocalyptic number.

It is an amenable number.

55001167503361 is a deficient number, since it is larger than the sum of its proper divisors (744671151).

55001167503361 is an equidigital number, since it uses as much as digits as its factorization.

55001167503361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 744671150.

The product of its (nonzero) digits is 283500, while the sum is 43.

The spelling of 55001167503361 in words is "fifty-five trillion, one billion, one hundred sixty-seven million, five hundred three thousand, three hundred sixty-one".

Divisors: 1 73867 744597283 55001167503361