Base | Representation |
---|---|
bin | 10000000000100000101… |
… | …01111101001111001001 |
3 | 1221120201112111022020211 |
4 | 20000100111331033021 |
5 | 33002430140131233 |
6 | 1100402535521121 |
7 | 54511153621654 |
oct | 10002025751711 |
9 | 1846645438224 |
10 | 550030005193 |
11 | 1a22a2664929 |
12 | 8a723b291a1 |
13 | 3cb38194c46 |
14 | 1c89b92489b |
15 | e492e535cd |
hex | 801057d3c9 |
550030005193 has 2 divisors, whose sum is σ = 550030005194. Its totient is φ = 550030005192.
The previous prime is 550030005181. The next prime is 550030005257. The reversal of 550030005193 is 391500030055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 537423880464 + 12606124729 = 733092^2 + 112277^2 .
It is a cyclic number.
It is not a de Polignac number, because 550030005193 - 213 = 550029997001 is a prime.
It is a super-2 number, since 2×5500300051932 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (550030005163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275015002596 + 275015002597.
It is an arithmetic number, because the mean of its divisors is an integer number (275015002597).
Almost surely, 2550030005193 is an apocalyptic number.
It is an amenable number.
550030005193 is a deficient number, since it is larger than the sum of its proper divisors (1).
550030005193 is an equidigital number, since it uses as much as digits as its factorization.
550030005193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10125, while the sum is 31.
The spelling of 550030005193 in words is "five hundred fifty billion, thirty million, five thousand, one hundred ninety-three".
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