Base | Representation |
---|---|
bin | 110011001110101011… |
… | …000110101001111001 |
3 | 12020222112101210220012 |
4 | 303032223012221321 |
5 | 1400123243412442 |
6 | 41134143111305 |
7 | 3655060620512 |
oct | 631653065171 |
9 | 166875353805 |
10 | 55007013497 |
11 | 21368030437 |
12 | a7b18a2535 |
13 | 52581b59c7 |
14 | 293b6d9a09 |
15 | 166e234582 |
hex | cceac6a79 |
55007013497 has 2 divisors, whose sum is σ = 55007013498. Its totient is φ = 55007013496.
The previous prime is 55007013421. The next prime is 55007013533. The reversal of 55007013497 is 79431070055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29544109456 + 25462904041 = 171884^2 + 159571^2 .
It is a cyclic number.
It is not a de Polignac number, because 55007013497 - 28 = 55007013241 is a prime.
It is not a weakly prime, because it can be changed into another prime (55001013497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27503506748 + 27503506749.
It is an arithmetic number, because the mean of its divisors is an integer number (27503506749).
Almost surely, 255007013497 is an apocalyptic number.
It is an amenable number.
55007013497 is a deficient number, since it is larger than the sum of its proper divisors (1).
55007013497 is an equidigital number, since it uses as much as digits as its factorization.
55007013497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 132300, while the sum is 41.
The spelling of 55007013497 in words is "fifty-five billion, seven million, thirteen thousand, four hundred ninety-seven".
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