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550110010011 = 3183370003337
BaseRepresentation
bin10000000000101010001…
…11001001101010011011
31221120221010000222020020
420000111013021222123
533003111130310021
61100414514401523
754513144635112
oct10002507115233
91846833028206
10550110010011
111a2333839711
128a7468902a3
133cb4b927583
141c8a83ccc79
15e499ea87c6
hex80151c9a9b

550110010011 has 4 divisors (see below), whose sum is σ = 733480013352. Its totient is φ = 366740006672.

The previous prime is 550110010007. The next prime is 550110010013. The reversal of 550110010011 is 110010011055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 550110010011 - 22 = 550110010007 is a prime.

It is a super-2 number, since 2×5501100100112 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (550110010013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91685001666 + ... + 91685001671.

It is an arithmetic number, because the mean of its divisors is an integer number (183370003338).

Almost surely, 2550110010011 is an apocalyptic number.

550110010011 is a deficient number, since it is larger than the sum of its proper divisors (183370003341).

550110010011 is a wasteful number, since it uses less digits than its factorization.

550110010011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183370003340.

The product of its (nonzero) digits is 25, while the sum is 15.

Adding to 550110010011 its reverse (110010011055), we get a palindrome (660120021066).

The spelling of 550110010011 in words is "five hundred fifty billion, one hundred ten million, ten thousand, eleven".

Divisors: 1 3 183370003337 550110010011