Base | Representation |
---|---|
bin | 111110100010110011111100… |
… | …0010000101110011010110111 |
3 | 2200010220002020222122222201022 |
4 | 1331011213320100232122313 |
5 | 1034102012242131030401 |
6 | 5230015504005251355 |
7 | 223610315225162114 |
oct | 17505477020563267 |
9 | 2603802228588638 |
10 | 550142231111351 |
11 | 14a324012313a7a |
12 | 51851300103b5b |
13 | 1a7c8260c81088 |
14 | 99bd05170b90b |
15 | 43906de09471b |
hex | 1f459f842e6b7 |
550142231111351 has 16 divisors (see below), whose sum is σ = 562074887301120. Its totient is φ = 538219086051360.
The previous prime is 550142231111273. The next prime is 550142231111353. The reversal of 550142231111351 is 153111132241055.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-550142231111351 is a prime.
It is a super-2 number, since 2×5501422311113512 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550142231111353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1655856290 + ... + 1656188496.
It is an arithmetic number, because the mean of its divisors is an integer number (35129680456320).
Almost surely, 2550142231111351 is an apocalyptic number.
550142231111351 is a deficient number, since it is larger than the sum of its proper divisors (11932656189769).
550142231111351 is a wasteful number, since it uses less digits than its factorization.
550142231111351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 346414.
The product of its (nonzero) digits is 18000, while the sum is 35.
The spelling of 550142231111351 in words is "five hundred fifty trillion, one hundred forty-two billion, two hundred thirty-one million, one hundred eleven thousand, three hundred fifty-one".
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