Base | Representation |
---|---|
bin | 1101000111011… |
… | …1010000100001 |
3 | 10211112000121121 |
4 | 3101313100201 |
5 | 103040430213 |
6 | 5243052241 |
7 | 1235420635 |
oct | 321672041 |
9 | 124460547 |
10 | 55014433 |
11 | 29066181 |
12 | 16511081 |
13 | b522926 |
14 | 7440dc5 |
15 | 4c6a88d |
hex | 3477421 |
55014433 has 2 divisors, whose sum is σ = 55014434. Its totient is φ = 55014432.
The previous prime is 55014391. The next prime is 55014439. The reversal of 55014433 is 33441055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52301824 + 2712609 = 7232^2 + 1647^2 .
It is a cyclic number.
It is not a de Polignac number, because 55014433 - 213 = 55006241 is a prime.
It is a super-2 number, since 2×550144332 = 6053175676622978, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55014398 and 55014407.
It is not a weakly prime, because it can be changed into another prime (55014439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27507216 + 27507217.
It is an arithmetic number, because the mean of its divisors is an integer number (27507217).
Almost surely, 255014433 is an apocalyptic number.
It is an amenable number.
55014433 is a deficient number, since it is larger than the sum of its proper divisors (1).
55014433 is an equidigital number, since it uses as much as digits as its factorization.
55014433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 25.
The square root of 55014433 is about 7417.1714959275. The cubic root of 55014433 is about 380.3285086291.
Adding to 55014433 its reverse (33441055), we get a palindrome (88455488).
The spelling of 55014433 in words is "fifty-five million, fourteen thousand, four hundred thirty-three".
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