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55020150001 = 187729312813
BaseRepresentation
bin110011001111011101…
…001101110011110001
312021000110010012210101
4303033131031303301
51400140124300001
641135332432401
73655310362405
oct631735156361
9167013105711
1055020150001
1121374493053
12a7b6178701
13525ab3509b
14293d359105
15167047ba01
hexccf74dcf1

55020150001 has 4 divisors (see below), whose sum is σ = 55049464692. Its totient is φ = 54990835312.

The previous prime is 55020149981. The next prime is 55020150007. The reversal of 55020150001 is 10005102055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 37351360225 + 17668789776 = 193265^2 + 132924^2 .

It is a cyclic number.

It is not a de Polignac number, because 55020150001 - 25 = 55020149969 is a prime.

It is a super-2 number, since 2×550201500012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55020150007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14654530 + ... + 14658283.

It is an arithmetic number, because the mean of its divisors is an integer number (13762366173).

Almost surely, 255020150001 is an apocalyptic number.

It is an amenable number.

55020150001 is a deficient number, since it is larger than the sum of its proper divisors (29314691).

55020150001 is a wasteful number, since it uses less digits than its factorization.

55020150001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29314690.

The product of its (nonzero) digits is 250, while the sum is 19.

Adding to 55020150001 its reverse (10005102055), we get a palindrome (65025252056).

The spelling of 55020150001 in words is "fifty-five billion, twenty million, one hundred fifty thousand, one".

Divisors: 1 1877 29312813 55020150001