Base | Representation |
---|---|
bin | 11001000001010011100010… |
… | …11000101010001100001001 |
3 | 21012210220100121020012012212 |
4 | 30200221301120222030021 |
5 | 24202423321414221213 |
6 | 313004012123314505 |
7 | 14406044425666364 |
oct | 1440516130521411 |
9 | 235726317205185 |
10 | 55020433351433 |
11 | 16593042279a50 |
12 | 62073b397ba35 |
13 | 2491534baca24 |
14 | d83008a3d0db |
15 | 65631b19c9a8 |
hex | 320a7162a309 |
55020433351433 has 16 divisors (see below), whose sum is σ = 60451038849600. Its totient is φ = 49662555084480.
The previous prime is 55020433351409. The next prime is 55020433351451. The reversal of 55020433351433 is 33415333402055.
It is a cyclic number.
It is not a de Polignac number, because 55020433351433 - 228 = 55020164915977 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55020433351463) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30863843 + ... + 32597816.
It is an arithmetic number, because the mean of its divisors is an integer number (3778189928100).
Almost surely, 255020433351433 is an apocalyptic number.
It is an amenable number.
55020433351433 is a deficient number, since it is larger than the sum of its proper divisors (5430605498167).
55020433351433 is a wasteful number, since it uses less digits than its factorization.
55020433351433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63462232.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 55020433351433 its reverse (33415333402055), we get a palindrome (88435766753488).
The spelling of 55020433351433 in words is "fifty-five trillion, twenty billion, four hundred thirty-three million, three hundred fifty-one thousand, four hundred thirty-three".
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