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55020433351433 = 1126929363461659
BaseRepresentation
bin11001000001010011100010…
…11000101010001100001001
321012210220100121020012012212
430200221301120222030021
524202423321414221213
6313004012123314505
714406044425666364
oct1440516130521411
9235726317205185
1055020433351433
1116593042279a50
1262073b397ba35
132491534baca24
14d83008a3d0db
1565631b19c9a8
hex320a7162a309

55020433351433 has 16 divisors (see below), whose sum is σ = 60451038849600. Its totient is φ = 49662555084480.

The previous prime is 55020433351409. The next prime is 55020433351451. The reversal of 55020433351433 is 33415333402055.

It is a cyclic number.

It is not a de Polignac number, because 55020433351433 - 228 = 55020164915977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55020433351463) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30863843 + ... + 32597816.

It is an arithmetic number, because the mean of its divisors is an integer number (3778189928100).

Almost surely, 255020433351433 is an apocalyptic number.

It is an amenable number.

55020433351433 is a deficient number, since it is larger than the sum of its proper divisors (5430605498167).

55020433351433 is a wasteful number, since it uses less digits than its factorization.

55020433351433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63462232.

The product of its (nonzero) digits is 972000, while the sum is 41.

Adding to 55020433351433 its reverse (33415333402055), we get a palindrome (88435766753488).

The spelling of 55020433351433 in words is "fifty-five trillion, twenty billion, four hundred thirty-three million, three hundred fifty-one thousand, four hundred thirty-three".

Divisors: 1 11 269 293 2959 3223 78817 866987 63461659 698078249 17071186271 18594266087 187783048981 204536926957 5001857577403 55020433351433