Base | Representation |
---|---|
bin | 10000000000110110110… |
… | …00001000100110011001 |
3 | 1221121012102211101102211 |
4 | 20000123120020212121 |
5 | 33003320033003101 |
6 | 1100433151355121 |
7 | 54515562254014 |
oct | 10003330104631 |
9 | 1847172741384 |
10 | 550215125401 |
11 | 1a2388104437 |
12 | 8a775b22aa1 |
13 | 3cb6763c526 |
14 | 1c8b835237b |
15 | e4a431dc51 |
hex | 801b608999 |
550215125401 has 4 divisors (see below), whose sum is σ = 550860161572. Its totient is φ = 549570089232.
The previous prime is 550215125347. The next prime is 550215125419. The reversal of 550215125401 is 104521512055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 272170890000 + 278044235401 = 521700^2 + 527299^2 .
It is a cyclic number.
It is not a de Polignac number, because 550215125401 - 213 = 550215117209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (550215125441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322516806 + ... + 322518511.
It is an arithmetic number, because the mean of its divisors is an integer number (137715040393).
Almost surely, 2550215125401 is an apocalyptic number.
It is an amenable number.
550215125401 is a deficient number, since it is larger than the sum of its proper divisors (645036171).
550215125401 is an equidigital number, since it uses as much as digits as its factorization.
550215125401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 645036170.
The product of its (nonzero) digits is 10000, while the sum is 31.
Adding to 550215125401 its reverse (104521512055), we get a palindrome (654736637456).
The spelling of 550215125401 in words is "five hundred fifty billion, two hundred fifteen million, one hundred twenty-five thousand, four hundred one".
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