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55023113 = 61139001
BaseRepresentation
bin1101000111100…
…1011000001001
310211112110112002
43101321120021
5103041214423
65243200345
71235455145
oct321713011
9124473462
1055023113
1129071752
12165160b5
13b526872
147444225
154c6d228
hex3479609

55023113 has 4 divisors (see below), whose sum is σ = 55038228. Its totient is φ = 55008000.

The previous prime is 55023077. The next prime is 55023119. The reversal of 55023113 is 31132055.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 19465744 + 35557369 = 4412^2 + 5963^2 .

It is a cyclic number.

It is not a de Polignac number, because 55023113 - 26 = 55023049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55023119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1613 + ... + 10613.

It is an arithmetic number, because the mean of its divisors is an integer number (13759557).

Almost surely, 255023113 is an apocalyptic number.

It is an amenable number.

55023113 is a deficient number, since it is larger than the sum of its proper divisors (15115).

55023113 is an equidigital number, since it uses as much as digits as its factorization.

55023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15114.

The product of its (nonzero) digits is 450, while the sum is 20.

The square root of 55023113 is about 7417.7566015609. The cubic root of 55023113 is about 380.3485099128.

Adding to 55023113 its reverse (31132055), we get a palindrome (86155168).

The spelling of 55023113 in words is "fifty-five million, twenty-three thousand, one hundred thirteen".

Divisors: 1 6113 9001 55023113