Base | Representation |
---|---|
bin | 1010001111111011… |
… | …01100111011010001 |
3 | 112012110121001010211 |
4 | 11013331230323101 |
5 | 42232043340213 |
6 | 2305553524121 |
7 | 253231662124 |
oct | 50775547321 |
9 | 15173531124 |
10 | 5502324433 |
11 | 2373a11871 |
12 | 1096873641 |
13 | 698c48998 |
14 | 3a2aa03bb |
15 | 2230cd53d |
hex | 147f6ced1 |
5502324433 has 2 divisors, whose sum is σ = 5502324434. Its totient is φ = 5502324432.
The previous prime is 5502324413. The next prime is 5502324449. The reversal of 5502324433 is 3344232055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4074013584 + 1428310849 = 63828^2 + 37793^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5502324433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5502324395 and 5502324404.
It is not a weakly prime, because it can be changed into another prime (5502324413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751162216 + 2751162217.
It is an arithmetic number, because the mean of its divisors is an integer number (2751162217).
Almost surely, 25502324433 is an apocalyptic number.
It is an amenable number.
5502324433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5502324433 is an equidigital number, since it uses as much as digits as its factorization.
5502324433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 31.
The square root of 5502324433 is about 74177.6545396253. The cubic root of 5502324433 is about 1765.4228010696.
Adding to 5502324433 its reverse (3344232055), we get a palindrome (8846556488).
The spelling of 5502324433 in words is "five billion, five hundred two million, three hundred twenty-four thousand, four hundred thirty-three".
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