Base | Representation |
---|---|
bin | 101000000010001110100… |
… | …1110101101000011011001 |
3 | 201111000111210000222021202 |
4 | 1100010131032231003121 |
5 | 1210122244413444433 |
6 | 15411424113043545 |
7 | 1105350126026144 |
oct | 120043516550331 |
9 | 21430453028252 |
10 | 5502343499993 |
11 | 183159250720a |
12 | 74a4838565b5 |
13 | 30bb3a8a7b12 |
14 | 150459d1d05b |
15 | 981dde69ee8 |
hex | 5011d3ad0d9 |
5502343499993 has 2 divisors, whose sum is σ = 5502343499994. Its totient is φ = 5502343499992.
The previous prime is 5502343499981. The next prime is 5502343500013. The reversal of 5502343499993 is 3999943432055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4613251031104 + 889092468889 = 2147848^2 + 942917^2 .
It is a cyclic number.
It is not a de Polignac number, because 5502343499993 - 210 = 5502343498969 is a prime.
It is not a weakly prime, because it can be changed into another prime (5502343499293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751171749996 + 2751171749997.
It is an arithmetic number, because the mean of its divisors is an integer number (2751171749997).
Almost surely, 25502343499993 is an apocalyptic number.
It is an amenable number.
5502343499993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5502343499993 is an equidigital number, since it uses as much as digits as its factorization.
5502343499993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141717600, while the sum is 65.
The spelling of 5502343499993 in words is "five trillion, five hundred two billion, three hundred forty-three million, four hundred ninety-nine thousand, nine hundred ninety-three".
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