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5502413155042 = 22751206577521
BaseRepresentation
bin101000000010010000101…
…1000011010101011100010
3201111000200122002211001101
41100010201120122223202
51210122420231430132
615411435042025014
71105351633055116
oct120044130325342
921430618084041
105502413155042
111831618862071
1274a4a304816a
1330bb4c15561b
14150465291746
15981e51287e7
hex5012161aae2

5502413155042 has 4 divisors (see below), whose sum is σ = 8253619732566. Its totient is φ = 2751206577520.

The previous prime is 5502413155039. The next prime is 5502413155097. The reversal of 5502413155042 is 2405513142055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 4217071709601 + 1285341445441 = 2053551^2 + 1133729^2 .

It is a super-3 number, since 3×55024131550423 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5502413154992 and 5502413155010.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375603288759 + ... + 1375603288762.

Almost surely, 25502413155042 is an apocalyptic number.

5502413155042 is a deficient number, since it is larger than the sum of its proper divisors (2751206577524).

5502413155042 is a wasteful number, since it uses less digits than its factorization.

5502413155042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2751206577523.

The product of its (nonzero) digits is 120000, while the sum is 37.

Adding to 5502413155042 its reverse (2405513142055), we get a palindrome (7907926297097).

The spelling of 5502413155042 in words is "five trillion, five hundred two billion, four hundred thirteen million, one hundred fifty-five thousand, forty-two".

Divisors: 1 2 2751206577521 5502413155042