Base | Representation |
---|---|
bin | 101000000010010000101… |
… | …1000011010101011100010 |
3 | 201111000200122002211001101 |
4 | 1100010201120122223202 |
5 | 1210122420231430132 |
6 | 15411435042025014 |
7 | 1105351633055116 |
oct | 120044130325342 |
9 | 21430618084041 |
10 | 5502413155042 |
11 | 1831618862071 |
12 | 74a4a304816a |
13 | 30bb4c15561b |
14 | 150465291746 |
15 | 981e51287e7 |
hex | 5012161aae2 |
5502413155042 has 4 divisors (see below), whose sum is σ = 8253619732566. Its totient is φ = 2751206577520.
The previous prime is 5502413155039. The next prime is 5502413155097. The reversal of 5502413155042 is 2405513142055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4217071709601 + 1285341445441 = 2053551^2 + 1133729^2 .
It is a super-3 number, since 3×55024131550423 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5502413154992 and 5502413155010.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375603288759 + ... + 1375603288762.
Almost surely, 25502413155042 is an apocalyptic number.
5502413155042 is a deficient number, since it is larger than the sum of its proper divisors (2751206577524).
5502413155042 is a wasteful number, since it uses less digits than its factorization.
5502413155042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2751206577523.
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 5502413155042 its reverse (2405513142055), we get a palindrome (7907926297097).
The spelling of 5502413155042 in words is "five trillion, five hundred two billion, four hundred thirteen million, one hundred fifty-five thousand, forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •