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5502551204131 is a prime number
BaseRepresentation
bin101000000010010100110…
…0111000010000100100011
3201111001001020212102210121
41100010221213002010203
51210123211102013011
615411500452541111
71105355230341442
oct120045147020443
921431036772717
105502551204131
111831689781423
1274a521321797
1330bb7192b987
14150479748d59
15982022e6e71
hex501299c2123

5502551204131 has 2 divisors, whose sum is σ = 5502551204132. Its totient is φ = 5502551204130.

The previous prime is 5502551204113. The next prime is 5502551204141. The reversal of 5502551204131 is 1314021552055.

Together with previous prime (5502551204113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5502551204131 - 25 = 5502551204099 is a prime.

It is a super-2 number, since 2×55025512041312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5502551204141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751275602065 + 2751275602066.

It is an arithmetic number, because the mean of its divisors is an integer number (2751275602066).

Almost surely, 25502551204131 is an apocalyptic number.

5502551204131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5502551204131 is an equidigital number, since it uses as much as digits as its factorization.

5502551204131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 5502551204131 its reverse (1314021552055), we get a palindrome (6816572756186).

The spelling of 5502551204131 in words is "five trillion, five hundred two billion, five hundred fifty-one million, two hundred four thousand, one hundred thirty-one".