Base | Representation |
---|---|
bin | 10000000001000111011… |
… | …10101010101101010011 |
3 | 1221121120012111110020220 |
4 | 20000203232222231103 |
5 | 33004111421000003 |
6 | 1100455115004123 |
7 | 54522213303366 |
oct | 10004356525523 |
9 | 1847505443226 |
10 | 550355250003 |
11 | 1a244a211099 |
12 | 8a7b4a39643 |
13 | 3cb8a6914b0 |
14 | 1c8ccbca0dd |
15 | e4b179c353 |
hex | 8023baab53 |
550355250003 has 32 divisors (see below), whose sum is σ = 792356577600. Its totient is φ = 337779486720.
The previous prime is 550355249971. The next prime is 550355250007. The reversal of 550355250003 is 300052553055.
It is not a de Polignac number, because 550355250003 - 25 = 550355249971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (550355250007) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 92014273 + ... + 92020253.
It is an arithmetic number, because the mean of its divisors is an integer number (24761143050).
Almost surely, 2550355250003 is an apocalyptic number.
550355250003 is a deficient number, since it is larger than the sum of its proper divisors (242001327597).
550355250003 is a wasteful number, since it uses less digits than its factorization.
550355250003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11879.
The product of its (nonzero) digits is 56250, while the sum is 33.
It can be divided in two parts, 5503552 and 50003, that added together give a palindrome (5553555).
The spelling of 550355250003 in words is "five hundred fifty billion, three hundred fifty-five million, two hundred fifty thousand, three".
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