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55040212153 = 149369397397
BaseRepresentation
bin110011010000101001…
…101111110010111001
312021001211212110220001
4303100221233302321
51400210243242103
641141330433001
73655643040553
oct632051576271
9167054773801
1055040212153
1121384846043
12a800a32761
13526203a894
142941c9c4d3
1516720e101d
hexcd0a6fcb9

55040212153 has 4 divisors (see below), whose sum is σ = 55409609700. Its totient is φ = 54670814608.

The previous prime is 55040212151. The next prime is 55040212177. The reversal of 55040212153 is 35121204055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 25088025664 + 29952186489 = 158392^2 + 173067^2 .

It is a cyclic number.

It is not a de Polignac number, because 55040212153 - 21 = 55040212151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55040212151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184698550 + ... + 184698847.

It is an arithmetic number, because the mean of its divisors is an integer number (13852402425).

Almost surely, 255040212153 is an apocalyptic number.

It is an amenable number.

55040212153 is a deficient number, since it is larger than the sum of its proper divisors (369397547).

55040212153 is a wasteful number, since it uses less digits than its factorization.

55040212153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 369397546.

The product of its (nonzero) digits is 6000, while the sum is 28.

The spelling of 55040212153 in words is "fifty-five billion, forty million, two hundred twelve thousand, one hundred fifty-three".

Divisors: 1 149 369397397 55040212153