Base | Representation |
---|---|
bin | 101000000011000100001… |
… | …0101010110010101010011 |
3 | 201111012011000020011020220 |
4 | 1100012020111112111103 |
5 | 1210134434420412201 |
6 | 15412322303004123 |
7 | 1105442505330402 |
oct | 120061025262523 |
9 | 21435130204226 |
10 | 5504140404051 |
11 | 1832324846893 |
12 | 74a8a5599643 |
13 | 30c065c52963 |
14 | 15058a82b639 |
15 | 98296ab1036 |
hex | 50188556553 |
5504140404051 has 16 divisors (see below), whose sum is σ = 7353195997440. Its totient is φ = 3662262865440.
The previous prime is 5504140404023. The next prime is 5504140404071. The reversal of 5504140404051 is 1504040414055.
It is not a de Polignac number, because 5504140404051 - 25 = 5504140404019 is a prime.
It is a super-3 number, since 3×55041404040513 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5504140404071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2279496 + ... + 4025466.
It is an arithmetic number, because the mean of its divisors is an integer number (459574749840).
Almost surely, 25504140404051 is an apocalyptic number.
5504140404051 is a deficient number, since it is larger than the sum of its proper divisors (1849055593389).
5504140404051 is a wasteful number, since it uses less digits than its factorization.
5504140404051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1748026.
The product of its (nonzero) digits is 32000, while the sum is 33.
The spelling of 5504140404051 in words is "five trillion, five hundred four billion, one hundred forty million, four hundred four thousand, fifty-one".
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