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5504140404051 = 398310691745971
BaseRepresentation
bin101000000011000100001…
…0101010110010101010011
3201111012011000020011020220
41100012020111112111103
51210134434420412201
615412322303004123
71105442505330402
oct120061025262523
921435130204226
105504140404051
111832324846893
1274a8a5599643
1330c065c52963
1415058a82b639
1598296ab1036
hex50188556553

5504140404051 has 16 divisors (see below), whose sum is σ = 7353195997440. Its totient is φ = 3662262865440.

The previous prime is 5504140404023. The next prime is 5504140404071. The reversal of 5504140404051 is 1504040414055.

It is not a de Polignac number, because 5504140404051 - 25 = 5504140404019 is a prime.

It is a super-3 number, since 3×55041404040513 (a number of 39 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (5504140404071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2279496 + ... + 4025466.

It is an arithmetic number, because the mean of its divisors is an integer number (459574749840).

Almost surely, 25504140404051 is an apocalyptic number.

5504140404051 is a deficient number, since it is larger than the sum of its proper divisors (1849055593389).

5504140404051 is a wasteful number, since it uses less digits than its factorization.

5504140404051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1748026.

The product of its (nonzero) digits is 32000, while the sum is 33.

The spelling of 5504140404051 in words is "five trillion, five hundred four billion, one hundred forty million, four hundred four thousand, fifty-one".

Divisors: 1 3 983 1069 2949 3207 1050827 1745971 3152481 5237913 1716289493 1866442999 5148868479 5599328997 1834713468017 5504140404051