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550422341593 is a prime number
BaseRepresentation
bin10000000001001111011…
…10100110011111011001
31221121201212202001121121
420000213232212133121
533004231104412333
61100505513005241
754523656464605
oct10004756463731
91847655661547
10550422341593
111a2484075a93
128a8133b3821
133cb9b552267
141c8d7a92505
15e4b760132d
hex8027ba67d9

550422341593 has 2 divisors, whose sum is σ = 550422341594. Its totient is φ = 550422341592.

The previous prime is 550422341563. The next prime is 550422341659. The reversal of 550422341593 is 395143224055.

550422341593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 540891115209 + 9531226384 = 735453^2 + 97628^2 .

It is a cyclic number.

It is not a de Polignac number, because 550422341593 - 25 = 550422341561 is a prime.

It is not a weakly prime, because it can be changed into another prime (550422341563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275211170796 + 275211170797.

It is an arithmetic number, because the mean of its divisors is an integer number (275211170797).

Almost surely, 2550422341593 is an apocalyptic number.

It is an amenable number.

550422341593 is a deficient number, since it is larger than the sum of its proper divisors (1).

550422341593 is an equidigital number, since it uses as much as digits as its factorization.

550422341593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 550422341593 in words is "five hundred fifty billion, four hundred twenty-two million, three hundred forty-one thousand, five hundred ninety-three".