Base | Representation |
---|---|
bin | 111110100100111010111000… |
… | …0100100010010010110010011 |
3 | 2200011220210020100010022210120 |
4 | 1331021311300210102112103 |
5 | 1034121234230123022003 |
6 | 5230400550422201323 |
7 | 223640254250565411 |
oct | 17511656044222623 |
9 | 2604823210108716 |
10 | 550432012314003 |
11 | 14a4259a6244606 |
12 | 518994b3283243 |
13 | 1a819692986321 |
14 | 99cd0a16142b1 |
15 | 4397eee576853 |
hex | 1f49d70912593 |
550432012314003 has 8 divisors (see below), whose sum is σ = 733909487793600. Its totient is φ = 366954605855208.
The previous prime is 550432012314001. The next prime is 550432012314013. The reversal of 550432012314003 is 300413210234055.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 550432012314003 - 21 = 550432012314001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (550432012314001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5724888 + ... + 33669546.
It is an arithmetic number, because the mean of its divisors is an integer number (91738685974200).
Almost surely, 2550432012314003 is an apocalyptic number.
550432012314003 is a deficient number, since it is larger than the sum of its proper divisors (183477475479597).
550432012314003 is a wasteful number, since it uses less digits than its factorization.
550432012314003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34510401.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 550432012314003 its reverse (300413210234055), we get a palindrome (850845222548058).
The spelling of 550432012314003 in words is "five hundred fifty trillion, four hundred thirty-two billion, twelve million, three hundred fourteen thousand, three".
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