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55045341121 = 355915466519
BaseRepresentation
bin110011010000111101…
…010011111111000001
312021002012112001111211
4303100331103333001
51400213101403441
641142032410121
73656034452041
oct632075237701
9167065461454
1055045341121
1121387729561
12a8026a6941
135263115284
142942835721
1516727a5a81
hexcd0f53fc1

55045341121 has 4 divisors (see below), whose sum is σ = 55060811200. Its totient is φ = 55029871044.

The previous prime is 55045341103. The next prime is 55045341173. The reversal of 55045341121 is 12114354055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55045341121 - 25 = 55045341089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55045341181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7729701 + ... + 7736818.

It is an arithmetic number, because the mean of its divisors is an integer number (13765202800).

Almost surely, 255045341121 is an apocalyptic number.

It is an amenable number.

55045341121 is a deficient number, since it is larger than the sum of its proper divisors (15470079).

55045341121 is a wasteful number, since it uses less digits than its factorization.

55045341121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15470078.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 55045341121 its reverse (12114354055), we get a palindrome (67159695176).

The spelling of 55045341121 in words is "fifty-five billion, forty-five million, three hundred forty-one thousand, one hundred twenty-one".

Divisors: 1 3559 15466519 55045341121