Base | Representation |
---|---|
bin | 11001000010001110111011… |
… | …00101001010100011100011 |
3 | 21012220221122101001102021000 |
4 | 30201013131211022203203 |
5 | 24203434114203341011 |
6 | 313030403354203043 |
7 | 14411253434301012 |
oct | 1441073545124343 |
9 | 235827571042230 |
10 | 55052313340131 |
11 | 165a5611740348 |
12 | 6211610423483 |
13 | 24945458c0073 |
14 | d84790a22a79 |
15 | 657084d80356 |
hex | 3211dd94a8e3 |
55052313340131 has 32 divisors (see below), whose sum is σ = 81633461690880. Its totient is φ = 36668041629408.
The previous prime is 55052313340117. The next prime is 55052313340153. The reversal of 55052313340131 is 13104331325055.
55052313340131 is a `hidden beast` number, since 5 + 50 + 5 + 231 + 3 + 340 + 1 + 31 = 666.
It is not a de Polignac number, because 55052313340131 - 211 = 55052313338083 is a prime.
It is a super-2 number, since 2×550523133401312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55052313340231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 133942120 + ... + 134352506.
It is an arithmetic number, because the mean of its divisors is an integer number (2551045677840).
Almost surely, 255052313340131 is an apocalyptic number.
55052313340131 is a deficient number, since it is larger than the sum of its proper divisors (26581148350749).
55052313340131 is a wasteful number, since it uses less digits than its factorization.
55052313340131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414920 (or 414914 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
Adding to 55052313340131 its reverse (13104331325055), we get a palindrome (68156644665186).
The spelling of 55052313340131 in words is "fifty-five trillion, fifty-two billion, three hundred thirteen million, three hundred forty thousand, one hundred thirty-one".
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