Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0000110111111001111111 |
3 | 1201101202120101021222111200 |
4 | 2332230113000313321333 |
5 | 3204200132304400210 |
6 | 43512014030550543 |
7 | 2521520355260625 |
oct | 276542700677177 |
9 | 51352511258450 |
10 | 13104331325055 |
11 | 41a2574449483 |
12 | 157785a068453 |
13 | 74096b934499 |
14 | 334378405515 |
15 | 17ad18c920c0 |
hex | beb17037e7f |
13104331325055 has 48 divisors (see below), whose sum is σ = 23151235423680. Its totient is φ = 6854593135104.
The previous prime is 13104331325027. The next prime is 13104331325153. The reversal of 13104331325055 is 55052313340131.
13104331325055 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 43 + 313 + 250 + 55 = 666.
It is not a de Polignac number, because 13104331325055 - 210 = 13104331324031 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5501982 + ... + 7515348.
It is an arithmetic number, because the mean of its divisors is an integer number (482317404660).
Almost surely, 213104331325055 is an apocalyptic number.
13104331325055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13104331325055 is a deficient number, since it is larger than the sum of its proper divisors (10046904098625).
13104331325055 is a wasteful number, since it uses less digits than its factorization.
13104331325055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2016160 (or 2016157 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
Adding to 13104331325055 its reverse (55052313340131), we get a palindrome (68156644665186).
The spelling of 13104331325055 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred twenty-five thousand, fifty-five".
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