Base | Representation |
---|---|
bin | 11001000010010011111011… |
… | …01111110111100011010001 |
3 | 21012221012120122102022012122 |
4 | 30201021331233313203101 |
5 | 24204010120112003213 |
6 | 313031530145304025 |
7 | 14411410143626423 |
oct | 1441117557674321 |
9 | 235835518368178 |
10 | 55055000500433 |
11 | 165a677055768a |
12 | 6212040335015 |
13 | 249488352c54b |
14 | d84967872813 |
15 | 657190c2ad08 |
hex | 32127dbf78d1 |
55055000500433 has 2 divisors, whose sum is σ = 55055000500434. Its totient is φ = 55055000500432.
The previous prime is 55055000500429. The next prime is 55055000500481. The reversal of 55055000500433 is 33400500055055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49095484471489 + 5959516028944 = 7006817^2 + 2441212^2 .
It is a cyclic number.
It is not a de Polignac number, because 55055000500433 - 22 = 55055000500429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55055000500393 and 55055000500402.
It is not a weakly prime, because it can be changed into another prime (55055000200433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27527500250216 + 27527500250217.
It is an arithmetic number, because the mean of its divisors is an integer number (27527500250217).
Almost surely, 255055000500433 is an apocalyptic number.
It is an amenable number.
55055000500433 is a deficient number, since it is larger than the sum of its proper divisors (1).
55055000500433 is an equidigital number, since it uses as much as digits as its factorization.
55055000500433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112500, while the sum is 35.
Adding to 55055000500433 its reverse (33400500055055), we get a palindrome (88455500555488).
The spelling of 55055000500433 in words is "fifty-five trillion, fifty-five billion, five hundred thousand, four hundred thirty-three".
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