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5505550506003 = 318199100839799
BaseRepresentation
bin101000000011101110001…
…1000011101100000010011
3201111022210021120202111010
41100013130120131200103
51210200331412143003
615413114234222003
71105522450105662
oct120073430354023
921438707522433
105505550506003
1118329888052a9
1274b019884903
1330c22c12a502
14150681c0cdd9
159832a79e003
hex501dc61d813

5505550506003 has 8 divisors (see below), whose sum is σ = 7341137440000. Its totient is φ = 3670165288008.

The previous prime is 5505550505977. The next prime is 5505550506047. The reversal of 5505550506003 is 3006050555055.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5505550506003 - 29 = 5505550505491 is a prime.

It is a super-2 number, since 2×55055505060032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5505550502003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50365303 + ... + 50474496.

It is an arithmetic number, because the mean of its divisors is an integer number (917642180000).

Almost surely, 25505550506003 is an apocalyptic number.

5505550506003 is a deficient number, since it is larger than the sum of its proper divisors (1835586933997).

5505550506003 is a wasteful number, since it uses less digits than its factorization.

5505550506003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100858001.

The product of its (nonzero) digits is 281250, while the sum is 39.

The spelling of 5505550506003 in words is "five trillion, five hundred five billion, five hundred fifty million, five hundred six thousand, three".

Divisors: 1 3 18199 54597 100839799 302519397 1835183502001 5505550506003