Base | Representation |
---|---|
bin | 10000000001100100101… |
… | …10100110101111010011 |
3 | 1221122012022011112220111 |
4 | 20000302112212233103 |
5 | 33010112223204111 |
6 | 1100535321422151 |
7 | 54531252612142 |
oct | 10006226465723 |
9 | 1848168145814 |
10 | 550600600531 |
11 | 1a2565759623 |
12 | 8a86303a957 |
13 | 3cbc9466817 |
14 | 1c913615759 |
15 | e4c80b3a21 |
hex | 80325a6bd3 |
550600600531 has 2 divisors, whose sum is σ = 550600600532. Its totient is φ = 550600600530.
The previous prime is 550600600447. The next prime is 550600600567. The reversal of 550600600531 is 135006006055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 550600600531 - 29 = 550600600019 is a prime.
It is a super-2 number, since 2×5506006005312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 550600600493 and 550600600502.
It is not a weakly prime, because it can be changed into another prime (550600600331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275300300265 + 275300300266.
It is an arithmetic number, because the mean of its divisors is an integer number (275300300266).
Almost surely, 2550600600531 is an apocalyptic number.
550600600531 is a deficient number, since it is larger than the sum of its proper divisors (1).
550600600531 is an equidigital number, since it uses as much as digits as its factorization.
550600600531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 550600600531 its reverse (135006006055), we get a palindrome (685606606586).
The spelling of 550600600531 in words is "five hundred fifty billion, six hundred million, six hundred thousand, five hundred thirty-one".
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