Base | Representation |
---|---|
bin | 10000000001100101111… |
… | …00011010010010011001 |
3 | 1221122012222211001111221 |
4 | 20000302330122102121 |
5 | 33010122242323001 |
6 | 1100540314052041 |
7 | 54531433056505 |
oct | 10006274322231 |
9 | 1848188731457 |
10 | 550610511001 |
11 | 1a25703084a1 |
12 | 8a86641a021 |
13 | 3cbcb5266c5 |
14 | 1c914a75305 |
15 | e4c8dc01a1 |
hex | 8032f1a499 |
550610511001 has 4 divisors (see below), whose sum is σ = 579590011600. Its totient is φ = 521631010404.
The previous prime is 550610510981. The next prime is 550610511071. The reversal of 550610511001 is 100115016055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 550610511001 - 25 = 550610510969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (550610511071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14489750271 + ... + 14489750308.
It is an arithmetic number, because the mean of its divisors is an integer number (144897502900).
Almost surely, 2550610511001 is an apocalyptic number.
It is an amenable number.
550610511001 is a deficient number, since it is larger than the sum of its proper divisors (28979500599).
550610511001 is a wasteful number, since it uses less digits than its factorization.
550610511001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28979500598.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 550610511001 its reverse (100115016055), we get a palindrome (650725527056).
The spelling of 550610511001 in words is "five hundred fifty billion, six hundred ten million, five hundred eleven thousand, one".
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