Base | Representation |
---|---|
bin | 11001000010100110110001… |
… | …00000000000101001100001 |
3 | 21012222011200101212202002112 |
4 | 30201103120200000221201 |
5 | 24204141322412122031 |
6 | 313040321431325105 |
7 | 14412215555533115 |
oct | 1441233040005141 |
9 | 235864611782075 |
10 | 55065113004641 |
11 | 165aaa8a823783 |
12 | 6213ba2b20795 |
13 | 249580561ab4c |
14 | d8524691d745 |
15 | 65758390d62b |
hex | 3214d8800a61 |
55065113004641 has 4 divisors (see below), whose sum is σ = 55099898295552. Its totient is φ = 55030327713732.
The previous prime is 55065113004637. The next prime is 55065113004673. The reversal of 55065113004641 is 14640031156055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55065113004641 - 22 = 55065113004637 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55065113204641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17392643081 + ... + 17392646246.
It is an arithmetic number, because the mean of its divisors is an integer number (13774974573888).
Almost surely, 255065113004641 is an apocalyptic number.
It is an amenable number.
55065113004641 is a deficient number, since it is larger than the sum of its proper divisors (34785290911).
55065113004641 is a wasteful number, since it uses less digits than its factorization.
55065113004641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34785290910.
The product of its (nonzero) digits is 216000, while the sum is 41.
The spelling of 55065113004641 in words is "fifty-five trillion, sixty-five billion, one hundred thirteen million, four thousand, six hundred forty-one".
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