Base | Representation |
---|---|
bin | 11001000011001011100101… |
… | …00110010100101010001001 |
3 | 21020001001200212121201020121 |
4 | 30201211302212110222021 |
5 | 24210002312311014123 |
6 | 313053351012423241 |
7 | 14413515430225333 |
oct | 1441456246245211 |
9 | 236031625551217 |
10 | 55084878219913 |
11 | 16608402771533 |
12 | 621799a317b21 |
13 | 249763547c6b9 |
14 | d8619d96a453 |
15 | 657d3dc4d75d |
hex | 321972994a89 |
55084878219913 has 2 divisors, whose sum is σ = 55084878219914. Its totient is φ = 55084878219912.
The previous prime is 55084878219901. The next prime is 55084878219929. The reversal of 55084878219913 is 31991287848055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32550185646729 + 22534692573184 = 5705277^2 + 4747072^2 .
It is a cyclic number.
It is not a de Polignac number, because 55084878219913 - 29 = 55084878219401 is a prime.
It is not a weakly prime, because it can be changed into another prime (55084878219013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27542439109956 + 27542439109957.
It is an arithmetic number, because the mean of its divisors is an integer number (27542439109957).
Almost surely, 255084878219913 is an apocalyptic number.
It is an amenable number.
55084878219913 is a deficient number, since it is larger than the sum of its proper divisors (1).
55084878219913 is an equidigital number, since it uses as much as digits as its factorization.
55084878219913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174182400, while the sum is 70.
The spelling of 55084878219913 in words is "fifty-five trillion, eighty-four billion, eight hundred seventy-eight million, two hundred nineteen thousand, nine hundred thirteen".
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