Base | Representation |
---|---|
bin | 11001000011101001101100… |
… | …01011101011010110100011 |
3 | 21020002121102112021100221101 |
4 | 30201310312023223112203 |
5 | 24210233414341034303 |
6 | 313105023111335231 |
7 | 14414630151132313 |
oct | 1441646613532643 |
9 | 236077375240841 |
10 | 55101044471203 |
11 | 16614249139395 |
12 | 621ab50381517 |
13 | 2499010804873 |
14 | d86c94a17443 |
15 | 658488133d1d |
hex | 321d362eb5a3 |
55101044471203 has 8 divisors (see below), whose sum is σ = 55720451402640. Its totient is φ = 54481644074880.
The previous prime is 55101044471159. The next prime is 55101044471267. The reversal of 55101044471203 is 30217444010155.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55101044471203 - 29 = 55101044470691 is a prime.
It is a super-2 number, since 2×551010444712032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55101044471273) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16441776 + ... + 19507282.
It is an arithmetic number, because the mean of its divisors is an integer number (6965056425330).
Almost surely, 255101044471203 is an apocalyptic number.
55101044471203 is a deficient number, since it is larger than the sum of its proper divisors (619406931437).
55101044471203 is a wasteful number, since it uses less digits than its factorization.
55101044471203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3267557.
The product of its (nonzero) digits is 67200, while the sum is 37.
Adding to 55101044471203 its reverse (30217444010155), we get a palindrome (85318488481358).
The spelling of 55101044471203 in words is "fifty-five trillion, one hundred one billion, forty-four million, four hundred seventy-one thousand, two hundred three".
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