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5510442433011 = 32636984084199
BaseRepresentation
bin101000000101111111111…
…1101101011100111110011
3201111210102012121101202220
41100023333331223213303
51210240341230324021
615415243505212123
71106054620565565
oct120137775534763
921453365541686
105510442433011
111834a6910748a
1274bb64031043
1330c82b779b89
141509c77bb335
1598514ea8cc6
hex502fff6b9f3

5510442433011 has 8 divisors (see below), whose sum is σ = 7375192915200. Its totient is φ = 3659660119752.

The previous prime is 5510442433003. The next prime is 5510442433049. The reversal of 5510442433011 is 1103342440155.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5510442433011 - 23 = 5510442433003 is a prime.

It is a super-2 number, since 2×55104424330112 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5510442433091) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3492041311 + ... + 3492042888.

It is an arithmetic number, because the mean of its divisors is an integer number (921899114400).

Almost surely, 25510442433011 is an apocalyptic number.

5510442433011 is a deficient number, since it is larger than the sum of its proper divisors (1864750482189).

5510442433011 is a wasteful number, since it uses less digits than its factorization.

5510442433011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6984084465.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5510442433011 its reverse (1103342440155), we get a palindrome (6613784873166).

The spelling of 5510442433011 in words is "five trillion, five hundred ten billion, four hundred forty-two million, four hundred thirty-three thousand, eleven".

Divisors: 1 3 263 789 6984084199 20952252597 1836814144337 5510442433011