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551102522341 = 71072333157873
BaseRepresentation
bin10000000010100000100…
…01010010001111100101
31221200111021121211012011
420001100101102033211
533012124221203331
61101101211354221
754546556102060
oct10012021221745
91850437554164
10551102522341
111a27a3008938
128a983152971
133cc79442587
141c96014b8d7
15e5071ab3b1
hex80504523e5

551102522341 has 16 divisors (see below), whose sum is σ = 638446333824. Its totient is φ = 465950329344.

The previous prime is 551102522297. The next prime is 551102522371. The reversal of 551102522341 is 143225201155.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551102522341 is a prime.

It is a super-2 number, since 2×5511025223412 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (551102522371) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1404420 + ... + 1753453.

It is an arithmetic number, because the mean of its divisors is an integer number (39902895864).

Almost surely, 2551102522341 is an apocalyptic number.

It is an amenable number.

551102522341 is a deficient number, since it is larger than the sum of its proper divisors (87343811483).

551102522341 is a wasteful number, since it uses less digits than its factorization.

551102522341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3158220.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 551102522341 its reverse (143225201155), we get a palindrome (694327723496).

The spelling of 551102522341 in words is "five hundred fifty-one billion, one hundred two million, five hundred twenty-two thousand, three hundred forty-one".

Divisors: 1 7 107 233 749 1631 24931 174517 3157873 22105111 337892411 735784409 2365246877 5150490863 78728931763 551102522341