Base | Representation |
---|---|
bin | 10000000010100011111… |
… | …11001000111011000000 |
3 | 1221200120021210220011010 |
4 | 20001101333020323000 |
5 | 33012204104220000 |
6 | 1101104120520520 |
7 | 54550355632212 |
oct | 10012177107300 |
9 | 1850507726133 |
10 | 551131320000 |
11 | 1a2808297a58 |
12 | 8a990920140 |
13 | 3cc823b6201 |
14 | 1c963cc65b2 |
15 | e509998d50 |
hex | 8051fc8ec0 |
551131320000 has 280 divisors, whose sum is σ = 1839241204416. Its totient is φ = 145591424000.
The previous prime is 551131319989. The next prime is 551131320067. The reversal of 551131320000 is 23131155.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 12818539 + ... + 12861461.
Almost surely, 2551131320000 is an apocalyptic number.
551131320000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 551131320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (919620602208).
551131320000 is an abundant number, since it is smaller than the sum of its proper divisors (1288109884416).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
551131320000 is a wasteful number, since it uses less digits than its factorization.
551131320000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43065 (or 43040 counting only the distinct ones).
The product of its (nonzero) digits is 450, while the sum is 21.
Adding to 551131320000 its reverse (23131155), we get a palindrome (551154451155).
The spelling of 551131320000 in words is "five hundred fifty-one billion, one hundred thirty-one million, three hundred twenty thousand".
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