Base | Representation |
---|---|
bin | 10000000010100011111… |
… | …11110111101011100001 |
3 | 1221200120022011121212111 |
4 | 20001101333313223201 |
5 | 33012204131332041 |
6 | 1101104124555321 |
7 | 54550360360453 |
oct | 10012177675341 |
9 | 1850508147774 |
10 | 551131511521 |
11 | 1a2808408938 |
12 | 8a9909b2b41 |
13 | 3cc82452436 |
14 | 1c963d362d3 |
15 | e5099d5981 |
hex | 8051ff7ae1 |
551131511521 has 4 divisors (see below), whose sum is σ = 580138433200. Its totient is φ = 522124589844.
The previous prime is 551131511507. The next prime is 551131511551. The reversal of 551131511521 is 125115131155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 551131511521 - 221 = 551129414369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (551131511551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14503460811 + ... + 14503460848.
It is an arithmetic number, because the mean of its divisors is an integer number (145034608300).
Almost surely, 2551131511521 is an apocalyptic number.
It is an amenable number.
551131511521 is a deficient number, since it is larger than the sum of its proper divisors (29006921679).
551131511521 is a wasteful number, since it uses less digits than its factorization.
551131511521 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29006921678.
The product of its digits is 3750, while the sum is 31.
Adding to 551131511521 its reverse (125115131155), we get a palindrome (676246642676).
The spelling of 551131511521 in words is "five hundred fifty-one billion, one hundred thirty-one million, five hundred eleven thousand, five hundred twenty-one".
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