Base | Representation |
---|---|
bin | 11001000100000000011010… |
… | …01101101011100100011011 |
3 | 21020010202220121010200022121 |
4 | 30202000031031223210123 |
5 | 24210433404430014121 |
6 | 313114401315402111 |
7 | 14415541341525253 |
oct | 1442001515534433 |
9 | 236122817120277 |
10 | 55113242032411 |
11 | 16619438367692 |
12 | 62213952b3337 |
13 | 249a20587b5c4 |
14 | d876d0980963 |
15 | 65894ddcb141 |
hex | 32200d36b91b |
55113242032411 has 2 divisors, whose sum is σ = 55113242032412. Its totient is φ = 55113242032410.
The previous prime is 55113242032399. The next prime is 55113242032421. The reversal of 55113242032411 is 11423024231155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55113242032411 - 25 = 55113242032379 is a prime.
It is a super-2 number, since 2×551132420324112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55113242032421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27556621016205 + 27556621016206.
It is an arithmetic number, because the mean of its divisors is an integer number (27556621016206).
Almost surely, 255113242032411 is an apocalyptic number.
55113242032411 is a deficient number, since it is larger than the sum of its proper divisors (1).
55113242032411 is an equidigital number, since it uses as much as digits as its factorization.
55113242032411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 55113242032411 its reverse (11423024231155), we get a palindrome (66536266263566).
The spelling of 55113242032411 in words is "fifty-five trillion, one hundred thirteen billion, two hundred forty-two million, thirty-two thousand, four hundred eleven".
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