Base | Representation |
---|---|
bin | 11001000100000011101110… |
… | …00000101010111110100100 |
3 | 21020010221111022001201201122 |
4 | 30202001313000222332210 |
5 | 24211001023323211022 |
6 | 313115253403313112 |
7 | 14415633333543314 |
oct | 1442016700527644 |
9 | 236127438051648 |
10 | 55115017007012 |
11 | 1661a169289346 |
12 | 62217ab81b798 |
13 | 249a429518a31 |
14 | d8781c5c1444 |
15 | 658a04b3e742 |
hex | 32207702afa4 |
55115017007012 has 24 divisors (see below), whose sum is σ = 99777519205560. Its totient is φ = 26607160724480.
The previous prime is 55115017006961. The next prime is 55115017007053. The reversal of 55115017007012 is 21070071051155.
It can be written as a sum of positive squares in 4 ways, for example, as 22516695270976 + 32598321736036 = 4745176^2 + 5709494^2 .
It is a super-3 number, since 3×551150170070123 (a number of 42 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45862598 + ... + 47048994.
It is an arithmetic number, because the mean of its divisors is an integer number (4157396633565).
Almost surely, 255115017007012 is an apocalyptic number.
It is an amenable number.
55115017007012 is a deficient number, since it is larger than the sum of its proper divisors (44662502198548).
55115017007012 is a wasteful number, since it uses less digits than its factorization.
55115017007012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1586911 (or 1586909 counting only the distinct ones).
The product of its (nonzero) digits is 12250, while the sum is 35.
Adding to 55115017007012 its reverse (21070071051155), we get a palindrome (76185088058167).
The spelling of 55115017007012 in words is "fifty-five trillion, one hundred fifteen billion, seventeen million, seven thousand, twelve".
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