Base | Representation |
---|---|
bin | 101000000110100100010… |
… | …0010100010111001000011 |
3 | 201111220120001210001200111 |
4 | 1100031020202202321003 |
5 | 1210300334433244011 |
6 | 15420004403132151 |
7 | 1106130034323325 |
oct | 120151042427103 |
9 | 21456501701614 |
10 | 5511660056131 |
11 | 183553345a789 |
12 | 750243974057 |
13 | 30c993b01928 |
14 | 150aa13b7615 |
15 | 98586d26121 |
hex | 503488a2e43 |
5511660056131 has 2 divisors, whose sum is σ = 5511660056132. Its totient is φ = 5511660056130.
The previous prime is 5511660056113. The next prime is 5511660056141. The reversal of 5511660056131 is 1316500661155.
Together with previous prime (5511660056113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5511660056131 is a prime.
It is a super-2 number, since 2×55116600561312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5511660056101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755830028065 + 2755830028066.
It is an arithmetic number, because the mean of its divisors is an integer number (2755830028066).
Almost surely, 25511660056131 is an apocalyptic number.
5511660056131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5511660056131 is an equidigital number, since it uses as much as digits as its factorization.
5511660056131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 40.
The spelling of 5511660056131 in words is "five trillion, five hundred eleven billion, six hundred sixty million, fifty-six thousand, one hundred thirty-one".
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